Skip to main content

Infosys Off Campus Drive 2021 | Freshers | System Engineer, OE | 2019/ 2020/ 2021 Batch | Across India




 


Infosys is the second-largest India-based IT services company by 2014 revenues, and the fifth largest employer of H-1B visa professionals in the United States in FY 2013. On 15 February 2015, its market capitalization was ₹ 263,735 crores ($42.51 billion), making it India’s sixth-largest publicly-traded company.

Company Website: www.infosys.com

Position: Systems Engineer/ Operations Executive

Experience: Freshers

Job Location: Across India

Interview Location: Virtual (Online)

Salary:

  • BE/ B.Tech/ MCA/ M.Sc – INR 3.25 LPA
  • ME/ M.Tech – INR 3.5 LPA
  • Diploma/ B.Sc/ BCA-Rs 2.22 LPA

Eligibility Criteria for Infosys Off Campus Drive 2021:

Systems Engineer:

  • BE/ B.Tech/ ME/ M.Tech in any discipline
  • MCA/ M.Sc (Computer Science/ Electronics / Mathematics/ Physics/ Statistics/ IT/ Information Science)
  • Consistently excellent academic track record
  • Candidates graduating in 2019/2020

Operations Executive/ Testing Executive:

  • BCA or B.Sc Graduates (Computer Science/ Electronics/ Mathematics/ Physics/ Statistics/ Information Technology/ Information Science only)
  • Candidates must be graduating from the 2019/2020/2021 batch
  • Company (such as – Infosys BPO) selection process in the last 6 months
  • Candidates should have excellent communication skills.
  • Candidates should not have any active/ standing backlogs
    A simple average aggregate of 60% throughout Class X, XII & Graduation
  • Candidates should not have participated in the Infosys Ltd and/or Infosys Group
  • Candidates should be willing to relocate and work in a 24×7 environment.

Operation Executive:

  • Diploma holders from – Computer Science, Information Technology, Electronics & Communication, Electrical & Electronics branches only
  • Candidates must have graduated from 2019 or 2020or 2021 batch
  • Simple average aggregate of, Class X – 60% or equivalent/Diploma – 60% or 6 (on 10)
  • Candidates should not have any active/standing backlogs
  • Candidates should not have participated in the Infosys Ltd and/or Infosys Group Company (such as – Infosys BPM) selection process in the last 6 months.
  • Candidates should have excellent communication skills
  • Candidates should be willing to relocate to any location as required by Infosys
  • Candidates should be willing to relocate and work in a 24×7 environment

Selection Procedure for Infosys Off Campus Drive 2021:

  • Online Assessment Test
  • Interviews (Virtual)

Aptitude Test Pattern for Infosys Off Campus Drive 2021:

Infosys has a regular pattern that consists of three rounds. A written test followed by a Technical and HR interview. The written test is an important segment where everybody fails to pass. Therefore the students who want to clear the interview have to be good at mathematics and logical reasoning skills.

  • Quantitative Ability – 10 Questions.
  • Reasoning Ability – 15 questions.
  • Verbal ability – 40 questions.

The total time allotted for the online written is one and a half hours. Aspirants who are willing to attend the interview should improve their time management and verbal ability. The details about the time allotted to the examination are given below.

  • Quantitative Ability – 35 minutes.
  • Reasoning Ability – 25 minutes.
  • Verbal ability – 35 minutes.

For more information and To Apply click below 👇.

Engineering / MCA / MSc. 2019/2020- Job Link ðŸ‘ˆ

BCA / BSc. 2019/2020/2021- Job Link ðŸ‘ˆ

Diploma 2019/2020/2021 - Job Link ðŸ‘ˆ

There is heavy traffic on the server you might face problems while filling the application.

Popular posts from this blog

Check whether a number is Seed of another number

 A number P is said to be the seed of another number Q if multiplying P with its digits equates to Q. Ex:-  123 is seed of 738 as    123 * 1 * 2 * 3 = 738  Java 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 public class Seed{ public static void main (String[] args){ int num1 = 123 , num2 = 738 ; num1 = Math. min (num1,num2); num2 = Math. max (num1,num2); System. out . println (checkSeed(num1, num2)); } public static boolean checkSeed ( int num1, int num2){ int seed = num1; while (num1> 0 ){ seed = seed * (num1% 10 ); num1 = num1 / 10 ; } if (seed==num2) return true ; else return false ; } } Python def checkSeed(num1,num2): seed = num1 while num1 > 0 : seed = seed * (num1 % 10 ) num1 = num1 // 10 if seed == n

Program to sort the first half of an array in ascending and second half in descending order

Ex:-  [2, 4, 3, 10, 5, 8] [2, 4, 3]  and [10, 5, 8] ====>  [2, 3, 4] ascending                                                              [10, 8, 5] descending [ 2, 3, 4, 10, 8, 5] is the required answer.  Java 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 public class ArraySort{ public static void main (String[] args){ int [] arr = { 2 , 4 , 3 , 10 , 5 , 8 }; //sorting first half in ascending order for ( int i= 0 ; i<(arr. length / 2 ); i++){ for ( int j=i+ 1 ; j<(arr. length / 2 ); j++){ if (arr[i]>arr[j]){ int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } //sorting second half in descending order for ( int i=(arr. length / 2 ); i<arr. length ; i++){ for ( int j=i+ 1 ; j<arr. length ; j++)

Write a method to move hyphens to the left and characters to the right in a string

 Ex:-     code--heist--   ==>     ----codeheist Note:-  Return null or None if str is empty. Java 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 public static String moveHyphens (String str) { if (str. length ()== 0 ) return null ; else { String result = "" ; for ( int i= 0 ; i<str. length (); i++){ char ch = str. charAt (i); if (ch== '-' ) result = ch + result; else result += ch; } return result; } } Python def moveHyphens (str): if len(str)== 0 : return None else : result = "" for char in str: if char== '-' : result = char + result; else : result += char return result