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Write a function to return sorted squared Array

 You have a sorted array of integers. Write a function that returns a sorted array containing the squares of those integers.

Ex:-

[ -6, -4, 1, 2, 3, 5 ]

output:-

[ 1, 4, 9, 16, 25, 36 ]

Java

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 import java.util.*;
 public class SquaredArray{
     public static void main(String []args){
        int[] arr = { -6, -4, 1, 2, 3, 5 };
        int[] result = sortSquaredArray(arr);
        for(int x: result)
            System.out.print(x+" ");
     }
     public static int[] sortSquaredArray(int[] arr){
        for(int i=0; i<arr.length; i++)
            arr[i] = arr[i] * arr[i] ;
        Arrays.sort(arr);
        return arr;
     }
 }

Java ( Another approach )

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 import java.util.*;
 public class SquaredArray{
     public static void main(String []args){
        int[] arr = { -6, -4, 1, 2, 3, 5 };
        int[] result = sortSquaredArray(arr);
        for(int x: result)
            System.out.print(x+" ");
     }
     public static int[] sortSquaredArray(int[] arr){
        int[] result = new int[arr.length];
        int left = 0, right = arr.length - 1;
        for(int i=arr.length-1; i>=0; i--){
            if(Math.abs(arr[left]) > arr[right]){
                result[i] = arr[left]*arr[left];
                left++;
            }
            else{
                result[i] = arr[right]*arr[right];
                right--;
            }
        }
        return result;
     }
 }

Python

arr = [ -6, -4, 1, 2, 3, 5 ]
for i in range(0,len(arr)):
    arr[i] = arr[i]*arr[i]
arr.sort()
print(arr)

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