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Nearest Smaller Element

Given an Array of N integers, the task is to find for each array element the nearest smaller element to its left. If the smaller element does not present then print -1.

Ex:- [ 2, 5, 1, 4, 8, 3, 2, 5 ] 

for 2 nearest smaller element to its left is not available so print -1

for 5 nearest smaller element to its left is 2 so print 2

for 1 nearest smaller element to its left is not available so print -1

for 4 nearest smaller element to its left is 1 so print 1

for 8 nearest smaller element to its left is 4 so print 4

for 3 nearest smaller element to its left is 1 so print 1

for 2 nearest smaller element to its left is 1 so print 1

for 5 nearest smaller element to its left is 2 so print 2

So the final answer will be -1  2  -1  1  4  1  1  2.

Java

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 public class NearestSmall{
     public static void main(String []args){
        int[] arr = { 1, 4, 8, 3, 2, 5 };
        for(int i=0; i<arr.length; i++){
            int j = i-1;
            while(j >= 0){
                if(arr[j]<arr[i]){
                    System.out.print(arr[j]+" ");
                    break;
                }
                j --;
            }
            if(j==-1)
                System.out.print("-1 ");
        }
     }
 }


Python


arr = [ 1, 4, 8, 3, 2, 5 ]
for i in range(0,len(arr)):
    j = i-1;
    while j>=0:
        if arr[j]<arr[i]:
            print(arr[j], end=" ")
            break
        j -= 1
    if j==-1:
        print("-1", end=" ")

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