Skip to main content

Check Array elements can make Arithmetic Progression

Example 1: 

Input: arr = [3,5,1]
Output: true
Explanation: We can reorder the elements as [1,3,5] or [5,3,1] with differences 2 and -2 respectively, between each consecutive elements.

Example 2: 

Input: arr = [1,2,4]
Output: false
Explanation: There is no way to reorder the elements to obtain an arithmetic progression. 

Constraints:

  • 2 < arr.length <= 1000
  • -10^6 <= arr[i] <= 10^6

Java

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
 import java.util.*;
 public class AP {
    public static void main(String args[]) {
      int[] arr = { 3, 5, 1 };
      System.out.println(checkAP(arr));
    }
    public static boolean checkAP(int[] arr){
        Arrays.sort(arr); // sort the array
        int diff = arr[1] - arr[0];  // difference
        for(int i=2; i<arr.length; i++)
            if(arr[i]-arr[i-1]!=diff)
                return false;
                
        return true;
    }
 }

Python

def checkAP(arr):
    arr.sort()
    diff = arr[1] - arr[0]
    for i in range(2, len(arr)):
        if arr[i]-arr[i-1] != diff:
            return False
    return True

arr = [ 3, 5, 1 ]
print(checkAP(arr))

Popular posts from this blog

Check whether a number is Seed of another number

 A number P is said to be the seed of another number Q if multiplying P with its digits equates to Q. Ex:-  123 is seed of 738 as    123 * 1 * 2 * 3 = 738  Java 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 public class Seed{ public static void main (String[] args){ int num1 = 123 , num2 = 738 ; num1 = Math. min (num1,num2); num2 = Math. max (num1,num2); System. out . println (checkSeed(num1, num2)); } public static boolean checkSeed ( int num1, int num2){ int seed = num1; while (num1> 0 ){ seed = seed * (num1% 10 ); num1 = num1 / 10 ; } if (seed==num2) return true ; else return false ; } } Python def checkSeed(num1,num2): seed = num1 while num1 > 0 : seed = seed * (num1 % 10 ) num1 = num1 // 10 if seed == n
Read more

Program to sort the first half of an array in ascending and second half in descending order

Ex:-  [2, 4, 3, 10, 5, 8] [2, 4, 3]  and [10, 5, 8] ====>  [2, 3, 4] ascending                                                              [10, 8, 5] descending [ 2, 3, 4, 10, 8, 5] is the required answer.  Java 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 public class ArraySort{ public static void main (String[] args){ int [] arr = { 2 , 4 , 3 , 10 , 5 , 8 }; //sorting first half in ascending order for ( int i= 0 ; i<(arr. length / 2 ); i++){ for ( int j=i+ 1 ; j<(arr. length / 2 ); j++){ if (arr[i]>arr[j]){ int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } //sorting second half in descending order for ( int i=(arr. length / 2 ); i<arr. length ; i++){ for ( int j=i+ 1 ; j<arr. length ; j++)
Read more

Write a method to move hyphens to the left and characters to the right in a string

 Ex:-     code--heist--   ==>     ----codeheist Note:-  Return null or None if str is empty. Java 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 public static String moveHyphens (String str) { if (str. length ()== 0 ) return null ; else { String result = "" ; for ( int i= 0 ; i<str. length (); i++){ char ch = str. charAt (i); if (ch== '-' ) result = ch + result; else result += ch; } return result; } } Python def moveHyphens (str): if len(str)== 0 : return None else : result = "" for char in str: if char== '-' : result = char + result; else : result += char return result
Read more