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Write algorithm to find the number with maximum exponent of 2 between the given range

   Assumption: a < b

   Note: If two or more numbers in the range have the same exponents of  2 , return the small number.

Java

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 public static int maxExponent(int a, int b){
    int max = 0
    for(int i=a; i<=b; i++){
        if(count2s(i)>count2s(max))
            max = i
    }
    return max;
 }

 public static int count2s(int num){
    int count = 0;
    while(num!=0 && num%2==0){
        count ++;
        num /= 2;
    }
    return count;
 }

Python

def count2s(num):
    count = 0
    while num%2==0 and num!=0:
        count += 1
        num = num//2
    return count
    
def maxExponent(a, b):
    max = 0
    for i in range(a,b+1):
        if(count2s(i)>count2s(max)):
            max = i
    return max


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